5x^2+9x=234

Solution for 5x^2+9x=234 equation:

5x^2+9x=234

We move all terms to the left:

5x^2+9x-(234)=0

a = 5; b = 9; c = -234;
Δ = b2-4ac
Δ = 92-4·5·(-234)
Δ = 4761
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4761}=69$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-69}{2*5}=\frac{-78}{10}
=-7+4/5
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+69}{2*5}=\frac{60}{10}
=6
$